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The oxide that gives hydrogen peroxide $\left(\mathrm{H}_2 \mathrm{O}_2\right)$ on the treatment with a dilute acid $\left(\mathrm{H}_2 \mathrm{SO}_4\right)$ is
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$\mathrm{Na}_2 \mathrm{O}_2$
$\mathrm{Na}_2 \mathrm{O}_2+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow \mathrm{Na}_2 \mathrm{SO}_4+\mathrm{H}_2 \mathrm{O}_2$
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