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Question: Answered & Verified by Expert
The oxidising ability of the given anions follows the order
Chemistryd and f Block ElementsKVPYKVPY 2017 (19 Nov SB/SX)
Options:
  • A $\mathrm{TiO}_{4}^{4-} < \mathrm{VO}_{4}^{3-} < \mathrm{CrO}_{4}^{2-} < \mathrm{MnO}_{4}^{-}$
  • B $\mathrm{VO}_{4}^{3-} < \mathrm{CrO}_{4}^{2-} < \mathrm{MnO}_{4}^{-} < \mathrm{TiO}_{4}^{4-}$
  • C $\mathrm{CrO}_{4}^{2-} < \mathrm{MnO}_{4}^{-} < \mathrm{VO}_{4}^{3-} < \mathrm{TiO}_{4}^{4-}$
  • D $\mathrm{VO}_{4}^{3-} < \mathrm{TiO}_{4}^{4-} < \mathrm{CrO}_{4}^{2-} < \mathrm{MnO}_{4}^{-}$
Solution:
2877 Upvotes Verified Answer
The correct answer is: $\mathrm{TiO}_{4}^{4-} < \mathrm{VO}_{4}^{3-} < \mathrm{CrO}_{4}^{2-} < \mathrm{MnO}_{4}^{-}$
It is decided by SRP value

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