The particle emitted in the decay of U 92 238 to U 92 234

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Question: Answered & Verified by Expert

The particle emitted in the decay of

{}_{92}^{238}U

to

{}_{92}^{234}U

PhysicsNuclear PhysicsNEET

Options:

A $2 α a n d 2 β$
B $1 α a n d 2 β$
C $1 α o n l y$
D $2 β a n d 2 α$

Solution:

1058 Upvotes Verified Answer

The correct answer is:

1 α a n d 2 β

{}_{92}^{238}U \overset{α}{\to} {}_{90}^{234}U \overset{β^{- 1}}{\to} {}_{91}^{234}U \overset{β^{- 1}}{\to} {}_{92}^{234}U

Number of

α

-particle =

1

Number of

β

-particle =

2

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