The path difference between the two waves : y 1 = a 1 sin ⁡ ω t - 2 πx λ and y 2 = a 2 cos ⁡ ω t - 2 πx λ + ϕ is

Question

The path difference between the two waves : y 1 = a 1 sin ⁡ ω t - 2 πx λ and y 2 = a 2 cos ⁡ ω t - 2 πx λ + ϕ is, λ 2 π ϕ, λ ϕ + π 2 2 π, 2 π λ ϕ - π 2, 2 π λ ϕ

MARKS App · Accepted Answer

Relation between phase difference and path difference. Δ ϕ = 2 π λ Δ x y 1 = a 1 sin ⁡ ω t - k x y 2 = a 2 cos ⁡ ω t - k x + ϕ y 2 = a 2 sin ( ωt - kx + ϕ + π 2 ) Δ x = Δ ϕ 2 π × λ = 1 2 π π 2 + ϕ λ

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