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The percentage of $\mathrm{C}, \mathrm{H}$ and $\mathrm{N}$ in an organic compound are $40 \%, 13.3 \%$ and $46.7 \%$, respectively, then the empirical formula is:
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The correct answer is:
$\mathrm{CH}_4 \mathrm{~N}$


Hence, empirical formula of compound is $\mathrm{CH}_4 \mathrm{~N}$.
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