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Question: Answered & Verified by Expert
The pH of 0.005M codeine (C18H21NO3) solution is 9.95. Calculate its ionization constant and pKb.
ChemistryIonic EquilibriumNEET
Options:
  • A Kb = 0.0158 × 10-4, pKb = 5.80
  • B Kb = 2.51 × 10-5, pKb = 4.60
  • C Kb = 5.01 × 10-6, pKb = 4.30
  • D Kb = 6.01 × 10-6, pKb = 4.80
Solution:
2211 Upvotes Verified Answer
The correct answer is: Kb = 0.0158 × 10-4, pKb = 5.80
Correct Option is : (A)
Kb = 0.0158 × 10-4, pKb = 5.80

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