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Question: Answered & Verified by Expert
The pH of 0.5 M aqueous solution of HF Ka=2×10-4 is
ChemistryIonic EquilibriumNEET
Options:
  • A 2
  • B 4
  • C 6
  • D 10
Solution:
2235 Upvotes Verified Answer
The correct answer is: 2
Ka=Cα2
2×104=0.5×α2
α=2×10-2
∴ H+=Cα=0.5×2×10-2=10-2
pH=2

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