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The $\mathrm{pH}$ of $10^{-8} \mathrm{M} \mathrm{HCl}$ solution is
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1966 Upvotes
Verified Answer
The correct answer is:
between 6 and 7
$\mathrm{pH}=-\log \left[\mathrm{H}^{+}\right]$
$$
\begin{aligned}
{\left[\mathrm{H}^{+}\right] } &=10^{-8}+10^{-7}=1.1 \times 10^{-7} \\
\mathrm{pH} &=-\log \left(1.1 \times 10^{-7}\right) \\
\mathrm{pH} &=7-\log (1.1)
\end{aligned}
$$
$\therefore$ It is between 6 and 7 .
$$
\begin{aligned}
{\left[\mathrm{H}^{+}\right] } &=10^{-8}+10^{-7}=1.1 \times 10^{-7} \\
\mathrm{pH} &=-\log \left(1.1 \times 10^{-7}\right) \\
\mathrm{pH} &=7-\log (1.1)
\end{aligned}
$$
$\therefore$ It is between 6 and 7 .
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