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Question: Answered & Verified by Expert
The pH of a solution which is twice as acidic as pure water is (Given: log 2 = 0.3)
ChemistryIonic EquilibriumNEET
Options:
  • A 7.0
  • B 3.5
  • C 6.7
  • D 14.0
Solution:
1621 Upvotes Verified Answer
The correct answer is: 6.7
In H2O,[H3O+]=1×10-7M
So [H3O+]soln.=2×10-7M
pH=-log[H3O+]
or pH=-log(2×10-7)
=-0.3010-(-7)=6.7

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