The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is 0.5 π . The wave velocity is

Question

The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is 0.5 π . The wave velocity is, 144 m s - 1, 384 m s - 1, 256 m s - 1, 720 m s - 1

MARKS App · Accepted Answer

Here, f = 120 Hz , x = 0.8 m and ϕ = 0.5 π . From, ϕ = 2 π λ x and λ = 2 πx ϕ = 2 π × 0.8 0.5 π = 3.2 m v = nλ = 120 × 3.2 = 384 m s - 1

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