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The photoelectric threshold of metal is $2000 \AA$. The energy of the electrons ejected from the surface by ultraviolet light of wavelength $1500 \AA$ is
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$2.0 \mathrm{eV}$
$\mathrm{E}_{\mathrm{k}}=\frac{\mathrm{hc}}{\mathrm{e}}\left(\frac{1}{\lambda}-\frac{1}{\lambda_{0}}\right)=2.0 \mathrm{eV}$
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