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The pOH value of a solution whose hydroxide ion concentration is $6.2 \times 10^{-9} \mathrm{~mol} /$ litre is
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Verified Answer
The correct answer is:
8.21
$-\log (\mathrm{OH})=\mathrm{pOH} ;-\log 6.2 \times 10^{-9}=\mathrm{pOH}$
$\therefore \mathrm{pOH}=8.21$
$\therefore \mathrm{pOH}=8.21$
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