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The point of intersection of tangents at the ends of the latus-rectum of the parabola $y^2=4 x$ is equal to
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$(-1,0)$
Equation of the tangent at $\left(x_1, y_1\right)$ on the parabola $y^2=4 a x$ is $y y_1=2 a\left(x+x_1\right)$
$\therefore$ In this case, $a=1$
The co-ordinates at the ends of the latus rectum of the parabola $y^2=4 x \quad$ are $\quad L(1,2)$ and $L_1(1,-2)$
$\therefore$ In this case, $a=1$
The co-ordinates at the ends of the latus rectum of the parabola $y^2=4 x \quad$ are $\quad L(1,2)$ and $L_1(1,-2)$
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