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The point of intersection of the normals to the parabola $y^2=4 x$ at the ends of its latus rectum is :
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The correct answer is:
$(3,0)$
$(3,0)$
We know that point of intersection of the normal to the parabola $y^2=4 a x$ at the ends of its latus rectum is $(3 a, 0)$
Hence required point of intersection $=(3,0)$
Hence required point of intersection $=(3,0)$
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