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The point to which the origin should be shifted so that the equation \(y^2-6 y-4 x+13=0\) is transformed to the form \(y^2+A x=0\) is
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Verified Answer
The correct answer is:
\((-1,3)\)
Given equation is
\(\begin{aligned}
y^2-6 y-4 x+13 & =0 \Rightarrow(y-3)^2=4(x-1) \\
\Rightarrow \quad(y-3)^2-4(x-1) & =0
\end{aligned}\)
By analysis of above form, it we shift the origin to \((-1,3)\), then it transformed to the \(y^2+4 x=0\).
Hence, option (c) is correct.
\(\begin{aligned}
y^2-6 y-4 x+13 & =0 \Rightarrow(y-3)^2=4(x-1) \\
\Rightarrow \quad(y-3)^2-4(x-1) & =0
\end{aligned}\)
By analysis of above form, it we shift the origin to \((-1,3)\), then it transformed to the \(y^2+4 x=0\).
Hence, option (c) is correct.
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