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Question: Answered & Verified by Expert
The points $(2,-2),(8,4),(4,6)$ and $(-1,1)$ in order are the vertices of which one of the following quadrilaterals?
MathematicsStraight LinesNDANDA 2007 (Phase 1)
Options:
  • A Square
  • B Rhombus
  • C Rectangle(but not square)
  • D Trapezium
Solution:
2582 Upvotes Verified Answer
The correct answer is: Trapezium
Let points be $\mathrm{A}(2,-2), \mathrm{B}(8,4), \mathrm{C}(4,6)$ and $\mathrm{D}(-1,1)$ in
order and are vertices of a quadrilateral. $\mathrm{AB}^{2}=(8-2)^{2}+(4+2)^{2}=36+36=72$
$\mathrm{BC}^{2}=(4-8)^{2}+(6-4)^{2}=16+4=20$
$\mathrm{CD}^{2}=(4+1)^{2}+(6-1)^{2}=25+25=50$
$\mathrm{AD}^{2}=(2+1)^{2}+(-2-1)^{2}=9+9=18$
Thus $\mathrm{AB} \neq \mathrm{BC} \neq \mathrm{CD} \neq \mathrm{AD}$
Hence, quadrilateral is a trapezium.

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