The points where the circle x 2 + y 2 - 3 x - 4 y + 2 = 0 cuts the x -axis are

Question

The points where the circle x 2 + y 2 - 3 x - 4 y + 2 = 0 cuts the x -axis are, ( 1 , 2 ) & ( 2 , 0 ), ( 2 , 0 ) & ( 3 , 0 ), ( 0 , 2 ) & ( 0 , 1 ), ( 1 , 0 ) & ( 2 , 0 )

MARKS App · Accepted Answer

Given that: x 2 + y 2 - 3 x - 4 y + 2 = 0 Circle cuts x - a x i s , So put y = 0 x 2 - 3 x + 2 = 0 ⇒ x - 1 x - 2 = 0 ⇒ x = 1 , 2 Points are 1 , 0 & 2 , 0 .

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