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Question: Answered & Verified by Expert
The position and velocity of a particle executing simple harmonic motion at t=0 are given by cm and cm s-1 respectively. If the angular frequency of the particle is 2 rad s-1, then the amplitude of oscillation (in cm)  is
PhysicsOscillationsNEET
Options:
  • A 3
  • B 4
  • C 5
  • D 6
Solution:
1468 Upvotes Verified Answer
The correct answer is: 5
Given, the position and velocity of the particle executing SHM .

y=3 cm

v=8 cm s-1

Angular frequency, ω=2 rad s-1

The velocity,

v=ωa2-y2

8=2a2-32

4=a2-32

16=a2-9

a2=25

a=5 cm

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