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Question: Answered & Verified by Expert
The position of a particle as a function of time t, is given by xt=at+bt2-ct3 where a, b and c are constants. When the particles zero acceleration, then its velocity will be:
PhysicsMotion In One DimensionJEE MainJEE Main 2019 (09 Apr Shift 2)
Options:
  • A a+b23c
  • B a+b22c
  • C a+b2c
  • D a+b24c
Solution:
2506 Upvotes Verified Answer
The correct answer is: a+b23c
x(t)=at+bt2-ct3
velocity v(t)=ddt(x)=ddtat+bt2-ct3
=a+2bt-3ct2
Acceleration =ddtv(t)=2b-6tc
acceleration=02b-6tc=0
t=b3c
velocity when t=b3c,
vt=b3c=a+2bb3c-3b3c2
=a+2b23c-b23c
=a+b23c

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