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Question: Answered & Verified by Expert
The position vector of a particle is determined by the expression r=2t2i^+3tj^+9k^. The magnitude of its displacement (in m) in first two seconds is
PhysicsMotion In Two DimensionsJEE Main
Solution:
2241 Upvotes Verified Answer
The correct answer is: 10
r=2t2i^+3tj^+9k^
At t=0,r1=9k^
At t=2s,r2=8i^+6j^+9k^
Δr=r2-r1=8i^+6j^
Δr=r2-r1=82+62=10m

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