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The position vector of a point lying on the line joining the points whose positions vectors are $\hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}}$ and $\hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}$ is :
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The correct answer is:
$\hat{\mathbf{i}}$
The position vector of mid point of line joining the points whose position vector are $\hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}}$ and $\hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}$.
$=\frac{\hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}}+\hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}}{2}=\frac{2 \hat{\mathbf{i}}}{2}=\hat{\mathbf{i}}$
$=\frac{\hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}}+\hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}}{2}=\frac{2 \hat{\mathbf{i}}}{2}=\hat{\mathbf{i}}$
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