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The position vector of the points which divides internally in the ratio $2: 3$ the join of the points $2 \mathbf{a}-3 \mathbf{b}$ and $3 \mathbf{a}-\mathbf{2 b}$, is
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The correct answer is:
$\frac{12}{5} \mathbf{a}-\frac{13}{5} \mathbf{b}$
Position vectors of the points which divides internally is,
$\frac{3(2 a-3 b)+2(3 a-2 b)}{5}=\frac{12 a-13 b}{5} \text {. }$
$\frac{3(2 a-3 b)+2(3 a-2 b)}{5}=\frac{12 a-13 b}{5} \text {. }$
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