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Question: Answered & Verified by Expert
The potential difference between point $A ~\&~ B$ is

PhysicsCurrent ElectricityJEE Main
Options:
  • A $\frac{20}{7} \mathrm{~V}$
  • B $\frac{40}{7} \mathrm{~V}$
  • C $\frac{10}{7} \mathrm{~V}$
  • D 0
Solution:
2089 Upvotes Verified Answer
The correct answer is: 0
The given circuit is a balanced Wheatstone bridge circuit. Hence potential difference between $A$ and $B$ is zero.

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