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The potential difference between two parallel plates is $10^4 \mathrm{~V}$. If the plates are separated by $0.5 \mathrm{~cm}$, the force on an electron between the plates is
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Verified Answer
The correct answer is:
$3.2 \times 10^{-13} \mathrm{~N}$
The force $F=\frac{e V}{d}$
$=\frac{1.6 \times 10^{-19} \times 10^4}{0.5 \times 10^{-2}}$
$=3.2 \times 10^{-13} \mathrm{~N}$
$=\frac{1.6 \times 10^{-19} \times 10^4}{0.5 \times 10^{-2}}$
$=3.2 \times 10^{-13} \mathrm{~N}$
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