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The potential energy of a particle in a force field is $U=\frac{A}{r^2}-\frac{B}{r}$, where $A$ and $B$ are positive constants and $r$ is the distance of particle from the centre of the field. For stable equilibrium, the distance of the particle is
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$2 A / B$
Given, the potential energy of a particle in a force field $U=\frac{A}{r^2}-\frac{B}{r^1}$
For stable equilibrium, $F=-\frac{d U}{d r}=0$
$0=-\frac{2 A}{r^3}+\frac{B}{r^2}$
or $\frac{2 A}{r}=B$
The distance of particle from the centre of the field
$r=\frac{2 A}{B}$
For stable equilibrium, $F=-\frac{d U}{d r}=0$
$0=-\frac{2 A}{r^3}+\frac{B}{r^2}$
or $\frac{2 A}{r}=B$
The distance of particle from the centre of the field
$r=\frac{2 A}{B}$
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