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Question: Answered & Verified by Expert
The potential energy of a particle of mass kg moving in the x-y plane is given by U=-7x+24y J, where x and y are in meters. If t=0, the particle starts from rest from the origin, then speed of the particle at t=s is
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Options:
  • A 5 m/s
  • B 10 m/s
  • C 14 m/s
  • D 17.5 m/s
Solution:
2094 Upvotes Verified Answer
The correct answer is: 10 m/s
F=-Uxi^-Uyj^

F=-x7x+24yi^+y-7x+24yj^

F=7i^-24j^

ma=7i^-24j^

a=7i^-24j^5

a=255=5 m/s2

v=u+at

v=0+5×2

v=10 m/s

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