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Question: Answered & Verified by Expert
The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=-7x+24y J, where x and y are given in metre. If the particle starts from rest, from the origin, then the speed of the particle at t=2 s is
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Options:
  • A 5 m/s
  • B 14 m/s
  • C 17.5 m/s
  • D 10 m/s
Solution:
1753 Upvotes Verified Answer
The correct answer is: 10 m/s
F = - U x i ^ - U y j ^ = 7 i ^ - 24 j ^

a x = F x m = 7 5 = 1.4 m/s 2

a y = F y m = - 24 5

                 =4.8  m/s 2 along negative yaxis

v x = a x t = 1.4 × 2

                 =2.8m/s along negative yaxis

and v y = 4.8 × 2 = 9.6 m/s

v = v x 2 + v y 2 = 10 m/s

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