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Question: Answered & Verified by Expert
The potential energy of a particle of mass 5 kg moving in the x- y plane is given by, U=-7x+24y J
where x and y being in metre. If the particle starts from rest from the origin, then the speed of the particle at t=2 s is :
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Options:
  • A 5 m s-1
  • B 14 m s-1
  • C 17 m s-1
  • D 10 m s-1
Solution:
1038 Upvotes Verified Answer
The correct answer is: 10 m s-1
F=-ΔUΔxi^+ΔUΔyj^=--7 i^+24 j^

F=72+242=25 N a=F/m=25/5=5 m s-2

v=u+at

=0+5 × 2=10 m s-1

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