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The potential of the electric field produced by point charge at any point $(x, y, z)$ is given by $V=3 x^{2}+5$, where $x, y$ are in metres and $V$ is in volts. The intensity of the electric field at $(-2,1,0)$ is
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The correct answer is:
$-12 \mathrm{Vm}^{-1}$
Potential $(V)=3 x^{2}+5$ Intensity of the electric field $=\frac{d V}{d x}=6 x$
$$
\begin{aligned}
\therefore \quad E \text { at } x &=-2 \\
&=6(-2)=-12 \mathrm{~V} / \mathrm{m}
\end{aligned}
$$
$$
\begin{aligned}
\therefore \quad E \text { at } x &=-2 \\
&=6(-2)=-12 \mathrm{~V} / \mathrm{m}
\end{aligned}
$$
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