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The potential of the electric field produced by point charge at any point $(x, y, z)$ is given by $\mathrm{V}=3 \mathrm{x}^{2}+5$, where $\mathrm{x}, \mathrm{y}$ are in metres and $\mathrm{V}$ is in volts. The intensity of the electric field at $(-2,1,0)$ is
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The correct answer is:
$-12 \mathrm{Vm}^{-1}$
Intensity of the electric field, $E=\frac{d V}{d x}=6 x$
Potential $(\mathrm{v})=3 \mathrm{x}^{2}+5$
$\therefore$ E at $x=-2$
$$
=6(-2)=-12 \mathrm{~V} / \mathrm{m}
$$
Potential $(\mathrm{v})=3 \mathrm{x}^{2}+5$
$\therefore$ E at $x=-2$
$$
=6(-2)=-12 \mathrm{~V} / \mathrm{m}
$$
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