The power factor of the following circuit will be, 0.2, 0.4, 0.6, 0.8

Z = R 2 + ( X L ⁡ - X c ⁡ ) 2 ⇒ Z = ( 40 + 40 ) 2 + ( 100 - 40 ) 2 = 100 Ω ⇒ cos ⁡ ϕ = R Z = 80 100 = 0.8

The power factor of the following circuit will be

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The power factor of the following circuit will be

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The correct answer is:

0.8

Z = \sqrt{R^{2} + (X_{L} - X_{c})^{2}}

\Rightarrow Z = \sqrt{(40 + 40)^{2} + (100 - 40)^{2}} = 100 Ω

\Rightarrow \cos ϕ = \frac{R}{Z} = \frac{80}{100} = 0.8

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