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The ppm level of $\mathrm{F}^{-}$in a $500 \mathrm{~g}$ sample of a tooth paste containing $0.2 \mathrm{~g} \mathrm{~F}^{-}$is
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400
400
$\begin{aligned} \text { ppm } & =\frac{\text { wt. of solute }}{\text { wt. of solvent }} \times 10^6 \\ & =\frac{0.2}{500} \times 10^6=400\end{aligned}$
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