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The principal organic product formed in the following reaction is
$\mathrm{CH}_2=\mathrm{CH}\left(\mathrm{CH}_2\right)_8 \mathrm{COOH}+\mathrm{HBr} \xrightarrow{\text { peroxide }}$
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$\mathrm{CH}_2=\mathrm{CH}\left(\mathrm{CH}_2\right)_8 \mathrm{COOH}+\mathrm{HBr} \xrightarrow{\text { peroxide }}$
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Verified Answer
The correct answer is:
$\mathrm{CH}_2 \mathrm{Br} \mathrm{CH}_2\left(\mathrm{CH}_2\right)_8 \mathrm{COOH}$
$\mathrm{CH}_2=\mathrm{CH}\left(\mathrm{CH}_2\right)_8 \mathrm{COOH}+\mathrm{HBr} \xrightarrow{\text { peroxide }} \mathrm{CH}_2 \mathrm{BrCH}_2\left(\mathrm{CH}_2\right)_8 \mathrm{COOH}$
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