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Question: Answered & Verified by Expert
The principal organic product formed in the following reaction is
$\mathrm{CH}_2=\mathrm{CH}\left(\mathrm{CH}_2\right)_8 \mathrm{COOH}+\mathrm{HBr} \xrightarrow{\text { peroxide }}$
ChemistryCarboxylic Acid DerivativesJEE Main
Options:
  • A $\mathrm{CH}_3 \mathrm{CHBr}\left(\mathrm{CH}_2\right)_8 \mathrm{COOH}$
  • B $\mathrm{CH}_2=\mathrm{CH}\left(\mathrm{CH}_2\right)_8 \mathrm{COBr}$
  • C $\mathrm{CH}_2 \mathrm{Br} \mathrm{CH}_2\left(\mathrm{CH}_2\right)_8 \mathrm{COOH}$
  • D $\mathrm{CH}_2=\mathrm{CH}\left(\mathrm{CH}_2\right), \mathrm{CHBr} \mathrm{COOH}$
Solution:
1825 Upvotes Verified Answer
The correct answer is: $\mathrm{CH}_2 \mathrm{Br} \mathrm{CH}_2\left(\mathrm{CH}_2\right)_8 \mathrm{COOH}$
$\mathrm{CH}_2=\mathrm{CH}\left(\mathrm{CH}_2\right)_8 \mathrm{COOH}+\mathrm{HBr} \xrightarrow{\text { peroxide }} \mathrm{CH}_2 \mathrm{BrCH}_2\left(\mathrm{CH}_2\right)_8 \mathrm{COOH}$

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