Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The principal value of
$\sin ^{-1}\left(-\frac{\sqrt{3}}{2}\right)$
MathematicsInverse Trigonometric FunctionsJEE Main
Options:
  • A $\frac{-2 \pi}{3}$
  • B $\frac{-\pi}{3}$
  • C $\frac{4 \pi}{3}$
  • D $\frac{5 \pi}{3}$
Solution:
1662 Upvotes Verified Answer
The correct answer is: $\frac{-\pi}{3}$
$\sin ^{-1}\left(\frac{-\sqrt{3}}{2}\right)=-\sin ^{-1}\left(\frac{\sqrt{3}}{2}\right)=-\frac{\pi}{3}$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.