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Question: Answered & Verified by Expert
The principal value of
$\sin ^{-1}\left(\sin \frac{5 \pi}{3}\right)$ is
MathematicsInverse Trigonometric FunctionsJEE Main
Options:
  • A $\frac{5 \pi}{3}$
  • B $-\frac{5 \pi}{3}$
  • C $-\frac{\pi}{3}$
  • D $\frac{4 \pi}{3}$
Solution:
1938 Upvotes Verified Answer
The correct answer is: $-\frac{\pi}{3}$
$\sin ^{-1}\left(\sin \frac{5 \pi}{3}\right)=\sin ^{-1}\left(-\frac{\sqrt{3}}{2}\right)=-\frac{\pi}{3}$

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