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The principal value of
$\sin ^{-1}\left(\sin \frac{5 \pi}{3}\right)$ is
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$\sin ^{-1}\left(\sin \frac{5 \pi}{3}\right)$ is
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The correct answer is:
$-\frac{\pi}{3}$
$\sin ^{-1}\left(\sin \frac{5 \pi}{3}\right)=\sin ^{-1}\left(-\frac{\sqrt{3}}{2}\right)=-\frac{\pi}{3}$
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