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Question: Answered & Verified by Expert
The principle of parallax is used in the determination of distances of very distant stars. The baseline $A B$ is the line joining the Earth's two locations six months apart in its orbit around the Sun. That is, the baseline is about the diameter of the Earth's orbit $\approx 3 \times 10^{11} \mathrm{~m}$. However, even the nearest stars are so distant that with such a long baseline, they show parallax only of the order of $1^{\prime \prime}$ (second) of are or so. A parsec is a convenient unit of length on the astronomical scale. It is the distance of an object that will show a parallax of 1" (second) of arc from opposite ends of a baseline equal to the distance from the Earth to the Sun. How much is a parsec in terms of metres?
PhysicsUnits and Dimensions
Solution:
2935 Upvotes Verified Answer
Length of base line ' $b$ ' $=$ distance between Earth and Sun $=1 \mathrm{~A} . \mathrm{U} .=1.5 \times 10^{11} \mathrm{~m}$
Parallax angle $(\theta)=1^{\prime \prime}=\frac{1}{60}=\frac{1^{\circ}}{60 \times 60}$ $=\frac{\pi}{180} \times \frac{1}{60 \times 60}$ radian
Now, $\theta=\frac{\text { arc }}{\text { radius }}=\frac{b}{D}$
$$
\begin{aligned}
&\therefore r=\frac{l}{\theta}=\frac{1.5 \times 10^{11}}{\frac{\pi}{180} \times \frac{1}{60 \times 60}} \\
&\quad=3.1 \times 10^{16} \mathrm{~m} \\
&\therefore \quad 1 \text { parsec }=3.1 \times 10^{16} \mathrm{~m} .
\end{aligned}
$$

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