Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The probability distribution of a random variable X is PX=X12: X=1,2,3,4,5,60: otherwise. Then, the conditional probability P32<X<72X>2 is
MathematicsProbabilityJEE Main
Options:
  • A 56
  • B 518
  • C 16
  • D 712
Solution:
2033 Upvotes Verified Answer
The correct answer is: 16
Let, A=32<X<72, B=X>2
AB=2<X<72
PAB=PABPB=P3P3+P4+P5+P6
=312312+412+512+612=16

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.