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The probability of happening of an event \( A \) is \( 0.5 \) and that of \( B \) is \( 0.3 \). If \( A \) and \( B \) are mutually
exclusiveevents, then the probability of neither A nor B is
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exclusiveevents, then the probability of neither A nor B is
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The correct answer is:
\( 0.2 \)
$P(A)=0.5$
$P(B)=0.3$
$P(A \cap B)=0$
$P(A \cup B)=P(A)+P(B)-P(A \cap B)$
$=0.5+0.3-0=0.8$
$\Rightarrow P(A \cup B)=1-P(A \cup B)$
$=1-0.8=0.2$
$P(B)=0.3$
$P(A \cap B)=0$
$P(A \cup B)=P(A)+P(B)-P(A \cap B)$
$=0.5+0.3-0=0.8$
$\Rightarrow P(A \cup B)=1-P(A \cup B)$
$=1-0.8=0.2$
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