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The probability that a non-leap year selected at random will have 53 Sunday is
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The correct answer is:
$1 / 7$
In a non-leap year,total number of days is 365 . Out of them, there are 52 weeks and 1 day extra. Thus, a non-leap year always has 52 Sunday. The remaining 1 day can be Sunday, Monday, Tuenday, Wednesday, Thursday, Friday and Sarurday. Out of these 7 cases, we have Sunday in one
case
$\therefore$ Total number of outcomes = 7
Number of favourable outcomes = 1
Hence, required probability $=\frac{1}{7}$
case
$\therefore$ Total number of outcomes = 7
Number of favourable outcomes = 1
Hence, required probability $=\frac{1}{7}$
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