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Question: Answered & Verified by Expert
The probability that an ordinary or a non-leap year has 53 sunday, is
MathematicsProbabilityJEE Main
Options:
  • A $\frac{2}{7}$
  • B $\frac{1}{7}$
  • C $\frac{3}{7}$
  • D None of these
Solution:
1271 Upvotes Verified Answer
The correct answer is: $\frac{1}{7}$
In a non-leap year, we have 365 days i.e., 52 weeks and one day. So, we may have any day of seven days. Therefore, 53 Sunday, required probability $=\frac{1}{7}$

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