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Question: Answered & Verified by Expert
The process is spontaneous at the given temperature, if
ChemistryThermodynamics (C)KCETKCET 2013
Options:
  • A $\Delta H$ is +ve and $\Delta S$ is -ve
  • B $\Delta H$ is -ve and $\Delta S$ is +ve
  • C $\Delta H$ is +ve and $\Delta S$ is +ve
  • D $\Delta H$ is +ve and $\Delta S$ is equal to zero
Solution:
1329 Upvotes Verified Answer
The correct answer is: $\Delta H$ is -ve and $\Delta S$ is +ve
According to Gibbs' energy equation
$\Delta G=\Delta H-T \Delta S$
when $\Delta H$ is negatie but $T \Delta S$ is positive, i.e., energy factor as well as the randomness factor favour the process. The process will be highly spontaneous and $\Delta G$ will be highly negative.

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