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The product obtained at anode when $50 \%$ $\mathrm{H}_2 \mathrm{SO}_4$ aqueous solution is electrolysed using platinum electrodes is :
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$\mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_8$
$50 \% \mathrm{H}_2 \mathrm{SO}_4$ aqueous solution can be electrolysed by using Pt electrodes as $2 \mathrm{H}_2 \mathrm{SO}_4 2 \mathrm{HSO}_4^{-}+2 \mathrm{H}^{+}$
$2 \mathrm{HSO}_4^{-} \longrightarrow \mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_8+2 e^{-}$(at anode)
$2 \mathrm{HSO}_4^{-} \longrightarrow \mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_8+2 e^{-}$(at anode)
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