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The product of oxidation of $\mathrm{I}^{-}$with $\mathrm{MnO}_4^{-}$in alkaline medium is
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$10_3^{-}$
$6 \mathrm{MnO} 4+1+6 \mathrm{OH}-----\gt6 \mathrm{MnO}+2 / \mathrm{O} 3+3 \mathrm{H} 2 \mathrm{O}$
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