The proposition p → ~ p ∧ ~ q is equivalent to :, q, ~ p ∨ q, ~ p ∧ q, ~ p ∨ ~ q

~ p ∧ ~ q = ~ p ∨ ~ ~ q By De Morgan's Laws. = ~ p ∨ q

The proposition p → ~ p ∧ ~ q is equivalent to :

Question: Answered & Verified by Expert

The proposition

p \to ~ (p \land ~ q)

is equivalent to :

MathematicsMathematical ReasoningJEE MainJEE Main 2020 (03 Sep Shift 1)

Options:

Solution:

1688 Upvotes Verified Answer

The correct answer is:

(~ p) \lor q

~ (p \land ~ q)

$= ~ p \lor ~ (~ q)$ By De Morgan's Laws.

$= (~ p) \lor q$

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