The quantity of electricity in Faraday needed to reduce 1 mol of Cr 2 O 7 2 - to Cr 3 + is

Question

The quantity of electricity in Faraday needed to reduce 1 mol of Cr 2 O 7 2 - to Cr 3 + is,

MARKS App · Accepted Answer

1 faraday of charge is the magnitude of charge of one mole of electrons.

According to the given reaction:
${C r}_{2} O_{7}^{2 -} + {6 e}^{-} ⟶ {2 C r}^{3 +}$

Reduction of $1 mol$ of ${C r}_{2} O_{7}^{2 -}$ to ${C r}^{3 +}$ requires $6$ moles of electrons. Hence, charge required $= 6 Faraday$

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