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Question: Answered & Verified by Expert
The radii of $F, F^{-}, O$ and $O^{-2}$ are in the order of
ChemistryClassification of Elements and Periodicity in PropertiesJEE Main
Options:
  • A $\mathrm{O}^{2-} \gt \mathrm{F}^{-} \gt \mathrm{O} \gt \mathrm{F}$
  • B $O^{2-} \gt F^{-} \gt F\gt0$
  • C $F^{-} \gt O^{2-} \gt F\gt0$
  • D $O^{2-} \gt O\gtF^{-} \gt F$
Solution:
2518 Upvotes Verified Answer
The correct answer is: $\mathrm{O}^{2-} \gt \mathrm{F}^{-} \gt \mathrm{O} \gt \mathrm{F}$
Atomic radius decreases on going from left to right in a period. Thus size of $O \gt F$. As $O^{2-}$ and $\mathrm{F}^{-}$are isoelectronic, therefore, size of $\mathrm{O}^{2-} \gt \mathrm{F}^{-}$.

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