The radii of two soap bubbles are r 1 and r 2 . In isothermal conditions, two meet together in a vacuum. Then the radius of the resultant bubble is given by

Question

The radii of two soap bubbles are r 1 and r 2 . In isothermal conditions, two meet together in a vacuum. Then the radius of the resultant bubble is given by, R ⁡ = r 1 + r 2 / 2, R ⁡ = r ⁡ 1 ( r ⁡ 1 r ⁡ 2 + r ⁡ 2 ), R ⁡ 2 = r ⁡ 1 2 + r ⁡ 2 2, R ⁡ = r ⁡ 1 + r ⁡ 2

MARKS App · Accepted Answer

Apply mole conservation n 1 + n 2 = n P 1 V 1 + P 2 V 2 = P V outside pressure is zero ( 4 S r 1 ) 4 3 π r 1 3 + 4 S r 2 4 3 π r 2 3 = 4 S R 4 3 π R 3 r 1 2 + r 2 2 = R 2

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