The radius of a wheel is R and its radius of gyration about its axis passing through its centre and perpendicular to its plane is K . If the wheel is rolling without slipping, the ratio of its rotational kinetic energy to its translational kinetic energy is

Question

The radius of a wheel is R and its radius of gyration about its axis passing through its centre and perpendicular to its plane is K . If the wheel is rolling without slipping, the ratio of its rotational kinetic energy to its translational kinetic energy is, K 2 R 2, R 2 K 2, R 2 R 2 + K 2, K 2 R 2 + K 2

MARKS App · Accepted Answer

Rotational KE Translational KE = 1 2 I ω 2 1 2 M v 2 = K 2 R 2 ( ∵ I = MK 2 , v = R ω )

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