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The radius of gyration of a thin uniform circular disc (of radius $R$ ) about an axis passing through its centre and lying in its plane is
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Verified Answer
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$R / 2$
Moment of inertia of the thin uniform circular disc of mass $M$ and radius $R$ about an axis passing through its centre and lying in its plane (i.e., about its diameter) is
From (i) and (ii), we get
$k^2=\frac{R^2}{4} \quad$ or $\quad k=\frac{R}{2}$
From (i) and (ii), we get
$k^2=\frac{R^2}{4} \quad$ or $\quad k=\frac{R}{2}$
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