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The radius of $\mathrm{La}^{3+}$ (Atomic number of $\mathrm{La}=57$ ) is $1.06 Å$. Which one of the following given values will be closest to the radius of $\mathrm{Lu}^{3+}$ (Atomic number of $\mathrm{Lu}=71$ ) ?
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The correct answer is:
$0.85 Å$
Ionic radii $\propto \frac{1}{z}$
Thus, $\frac{z_{2}}{z_{1}} \Rightarrow \frac{1.06}{\left(\text { Ionic radii of } \mathrm{Lu}^{3+}\right)}=\frac{71}{57}$
$\Rightarrow$ Ionic radii of $\mathrm{Lu}^{3+}=0.85 Å$
Thus, $\frac{z_{2}}{z_{1}} \Rightarrow \frac{1.06}{\left(\text { Ionic radii of } \mathrm{Lu}^{3+}\right)}=\frac{71}{57}$
$\Rightarrow$ Ionic radii of $\mathrm{Lu}^{3+}=0.85 Å$
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